Missing DI, Data Interpretation Questions for IBPS PO, IBPS Clerk, NIACL, NICL, SBI PO, RBI Grade B, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams.
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Directions (1-5): In the given table data is given about the shop.Some electronic goods are sold by a shop. Some data is missing. Study the table carefully and answer the questions based on data in table and particular questions.
- What is the ratio of the cost price of mobile and cost price of laptop?
A) 4:2
B) 5:3
C) 6:4
D) 5:4
E) None of these
View Answer
Option D
Solution:
Cost Price of mobile = 25000 * 100/ (100+25) = 20000
Cost Price of laptop = 20000 * 100/ (100+25) = 16000
Required Ratio = 20000 : 16000 = 5 : 4
- Market Price of T.V is how much percent more than the cost price of T.V ?
A) 37.5 %
B) 35.5%
C) 36.0%
D) 40.7%
E) 32.6%
View Answer
Option A
Solution:
Amount of profit on T.V = 2000
Cost Price = 2000* 100/10 = 20000
Selling Price = 20000 + 2000 = 22000
Market Price = Selling Price * 100 / (100 – Discount%)
= 20000 * 100 /80 = 27500
Required Percentage = [(27500 -20000) /20000] * 100 = 37.5%
- What is the ratio between the percentage of profit and percentage of discount of Mobile ?
A) 3:2
B) 4:3
C) 2:3
D) 4:5
E) 4:3
View Answer
Option C
Solution:
Percentage of profit on Mobile = 25%
Percentage of discount on Mobile = [40000 – 25000/40000]*100
. = 37.5%
Required Ratio = 25 : 37.5
. = 2 : 3
- Selling Price of D.V.D is what percent of cost price of A.C ?
A) 5.6%
B) 7.2%
C) 5.3%
D) 3.4%
E) None of these
View Answer
Option C
Solution:
Market Price of D.V.D = 500 * 100/20 = 2500
Selling Price of D.V.D = 2500 – 500 = 2000
Selling Price of A.C = 50000 * 60 / 100 = 30000
Cost Price of A.C = 30000 * 100/80 = 37500
Required Percentage = (2000/37500)*100 = 5.3%
- What is the amount (in Rupees) of profit /loss of shop by selling all electronic goods ?
A) 5000
B) 5700
C) 5600
D) 5200
E) 5500
View Answer
Option B
Solution:
Selling Price of A.C = 50000 * 60/100 = 30000
Loss on A.C = 30000 * 100/80 – 3000 = Rs.7500
Market Price of D.V.D = 500 * 100 /20 = 2500
Selling Price of D.V.D = 2500 – 500 = 2000
Profit on D.V.D =2000 – 1800 = Rs.200
Profit on T.V = Rs. 2000
Profit on Mobile = 25000 – 25000 * 100/25 = Rs. 5000
Profit on Laptop = 20000 – 20000 * 100 / 125 = Rs. 4000
Profit on Radio = 10,000 * 20 /100 = Rs.2000Total Profit = -7500 + 200 + 2000 + 5000 + 4000 + 2000
= Rs. 5700
Directions (6-10): The given tables show the time taken by filling and emptying pipes to fill and empty a tank respectively. Some data is missing. Study the table carefully and answer the questions based on data in table and particular questions.
- Pipes B and D are to fill the tank. They both are opened. After 8 minutes pipe R was also opened. It took 3 11/39 minutes more to fill the tank. In how much time pipe R can empty the tank?
A) 24 minutes
B) 48 minutes
C) 50 minutes
D) 60 minutes
E) 72 minutes
View Answer
Option C
Solution:
B+D = 1/25 + 1/40 = 13/200
Worked for 8 minutes, so did 13/200 * 8 = 13/25 work
So 200/13 – 8 = 96/13 minutes left to complete work,
But after R was opened, it took 3 11/39 minutes more, means total 96/13 + 128/39 = 416/39 = 32/3 minutes
So now B+D – R
13/25 + (13/200 – 1/R) * 32/3 = 1
Solve, x = 50 minutes
- Pipes A, C and D are opened to fill a tank. After 10 minutes A and D were closed and C had to fill the remaining tank. But accidentally at the same time pipe Q was also opened which was closed after 3 minutes. Now C filled the tank. If pipe Q was not opened, how much time would have been saved?
A) 1 minute
B) 5 minutes
C) 3 minutes
D) 4 minutes
E) 2 minutes
View Answer
Option E
Solution:
A+C+D = 1/24 + 1/48 + 1/40 = 7/80
Worked for 10 minutes, so filled 7/80 * 10 = 7/8th of tank
Now C and Q are opened for 3 minutes — (1/48 – 1/72)* 3 = 1/48th filled now
So 7/8 + 1/48 + 1/48 *x = 1
Solve, x = 5 minutes
So total time = 10+3+5 = 18 minutes
If Q was not opened::
1/8th of tank was to be filled by C
So 1/48 * u = 1/8,
Solve, u = 6
So total time here = 10+6 = 16 minutes
So time that would have been saved = 18-16 = 2 minutes
- 11/40th of a tank was filled. Pipes C and D were opened. After some time pipe P was also opened. Pipe P was closed after time equal to the time it was opened at the starting . If after closing pipe P, the tank was filled in 6 minutes, find what fraction of tank was filled by pipe C?
A) 7/8th
B) 3/8th
C) 2/7th
D) 5/7th
E) None of these
View Answer
Option B
Solution:
C+D = 1/48 + 1/40 = 11/240
Let after x minutes P was opened, so P was opened for x minutes [as given]
So
11/40 + (1/48 + 1/40) * x + (1/48 + 1/40 – 1/60)*x + (1/48 + 1/40) * 6 = 1
OR 11/40 + (1/48 + 1/40) * 2x – 1/60 * x + (1/48 + 1/40) * 6 = 1
Solve, x = 6 minutes
So C was opened for 2x+6 = 18 minutes
So filled 1/48 * 18 = 3/8 of tank
- Pipe D was to fill a tank. To increase its efficiency, pipe A and C were opened for 2 minutes each starting with pipe A, then C and so on. This procedure ran for 16 minutes, after which pipe A and C were closed. Accidentally pipe S was opened and now it took 4 minutes more to fill the tank. Find in how much time pipe S can empty 3/40th of tank.
A) 11 minutes
B) 12 minutes
C) 3 minutes
D) 7 minutes
E) 6 minutes
View Answer
Option E
Solution:
For 2 minutes A and D. So
(1/24 + 1/40)* 2= 2/15
For next 2 minutes C and D. So
(1/48 + 1/40)* 2= 11/120
So in 4 minutes — 2/15 + 11/120 = 9/40
Procedure ran for 16 minutes, so multiply by 4 both sides
In 16 minutes, tank filled = 9/40 * 4 = 9/10
Now 1/10 tank left which D can fill in 4 minutes, but with D and S opened, took 4 more minutes, so 8 minutes
So (1/40 – 1/x) * 8 = 1/10
Solve, x = 80 minutes
Full tank in 80 minutes so 3/40th in 3/40 * 80 = 6 minutes
- To fill an empty tank all filling pipes A, B, C and D are opened one by one in same order. A and C are opened for 4 minutes each while B and D for 5 minutes each. In this way, in how much time the tank will be filled (approximately)?
A) 30 minutes
B) 32 minutes
C) 27 minutes
D) 22 minutes
E) 35 minutes
View Answer
Option A
Solution:
A for 4 minutes = 1/24 * 4 = 1/6
B for 5 minutes = 1/25 * 5 = 1/5
C for 4 minutes = 1/48 * 4 = 1/12
D for 5 minutes = 1/40 * 5 = 1/8
So in 18 minutes (4+5+4+5), tank filled is 1/6 + 1/5 + 1/12 + 1/8 = 23/40
Next A’s turn for 4 minutes = 1/6
Next B’s turn for 5 minutes = 1/5
Filled now = 23/40 + 1/6 + 1/5 = 113/120
Now 7/120 is left
Now C’s turn, full tank in 48 minutes, so 7/120 in 48 * 7/120 = 14/5 minutes
So total = 18 + 4 + 5+ 14/5 = 27 + 3 = 30 mins approx
In question 2nd Given discount is 25% bt in ans u hv used 20% as discount. Is there any typing mistake??
hmm mistake hai esme
yes
In question 2nd
Selling Price = 20000 + 2000 = 22000
mrp=22000*125/100=27500
6 qs by unit method?
In question number 9
2 min work of C and D will be 11/120 not 1/120
yes answer according to that only
U sits exactly between S and O and they face in opposite directions……………..inki directions kya hogi ???
neighbours of U face opposite directions i.e S and O .
There are 9 people-M, N, O, P, Q, R, S, T and U are sitting around a circular table out of which some are females and some are males. Some are facing towards the center and some are facing away from the centre. The following information is known about them.
i. Q’s neighbours face in same direction as that of O’s sister who is sitting to the immediate right of O.
ii. The female sitting between N and P is not Q.
iii. Q sits 4th to the right of R.
iv. R’s spouse is N.
v. U sits exactly between S and O and they face in opposite directions.
vi. S is a male sitting with two females and one of them has husband facing towards the centre who is sitting 3rd to the left of N.
vii. The person sitting 2nd to the left T is the wife of T and they face in same direction.
viii. M’s immediate neighbours are S and N.
ix. U’s spouse sits second to the right of U.
x. P sits second to the left of N.
xi. The person 4th to the left of T sits faces in a direction opposite to that of T but same as P.
Tough puzzle…… but at last done……..
https://uploads.disquscdn.com/images/e1f73b70e428ab2f04263da65423525d11311899450b398c3b2e9caa64a8b051.jpg
Kitni possibility ban rahi hai
4 possibility bane…..
Yes start R se kiya mean q is 4th right of r?? R dono face se compare kiya??
yes… R dono face se hi compare kiya…
Blood relation &direction kaise decide kiya 2nd left of T wife of T to in facing kaise decide kiya??
At 1st follow R ki 4th right me Q (2 no face se compare kerke)……. then, mai ne S M N ki sitting place arrange kiya…… then follow N ki 2nd left me P…. fir follow U sits exactly between S and O nd they face opposite direction…… itna ho ja ne ke bad srif T ki jaga khali rahigi…..yeha pe 2 possiblity bane gi…… ek T ka 2nd left pe Q , T ka wife ho sakte hain or T ka 2nd left pe P , T ka wife ho sakte hain…..aase follow ker ke 1 possibility out ho jaye gi…….
okk thx got it..
Aesi puzzles ko kahan se start krna chahiye.
At 1st follow R ki 4th right me Q (2 no face se compare kerke)……. then, mai ne S M N ki sitting place arrange kiya…… then follow N ki 2nd left me P…. fir follow U sits exactly between S and O nd they face opposite direction…… itna ho ja ne ke bad srif T ki jaga khali rahigi…..yeha pe 2 possiblity bane gi…… ek T ka 2nd left pe Q , T ka wife ho sakte hain or T ka 2nd left pe P , T ka wife ho sakte hain…..aase follow ker ke 1 possibility out ho jaye gi…….
7/10 ty az
6 to 10 kiye kya tell me
Hardly 2 correct aaya 6 the&10 the que
vhi btaao
6th mai
B+D=13/200
After 8 min means =13/25 work in 8 min me b&d work karenge
So remaining work 200/13-8=96/13 left
R open hone ke bad additional work bd&r milke
b+d-r=96/13+128/39=32/3 min
Total work lelo
B+D-R
13/25+(13/200-1/R)32/3=1
X=50
ye to solution me hi diya hai
Ha kya samja to batao
anyone done 8th question
I am gtting x=28/3………but in sol it is given x=6 ????
Nice mam plz aese questions post kiya kro
anyone getting 8th question ??
x=6 comes only ..
solve the equation once again plz.. u will get 6 as value .
Ha question m printing mistake h 1/40 filled dia h bt solve krte time 11/40 liya h
And isko 11/40 suppose krke kre to
Tw 240
11/40 alrdy filled so remaining
240*29/40=174
C=5
D=6
P=-4
In 6 min c+d=6*11=66
Remain=174-66=108
Now
2t(5+6)-t4=108
18t=108
T=6
C wrk fr 18 min
C=18*5/240=3/8
bm band ho gya na ab ?
Ha yr
qs 9????????//
Or yha ka kuch smjh ni aa rha live quiz hoti b h ya ni
Yes hoti hai
Can u see the discussion zone on top left of page?
New link is posted at 8PM each day
Join there
Ok thnx mam
hoti h english or banking ki 8pm new link ata h…right side me disscussion zone h wha ayega …….or haan channal ko subscribe kr do ..to notification mil jayegenge
aj 7 pm mths quiz hog AZ pr…new link ayega
A boy has 3 library tickets and 8 books of his interest in the library of these 8, he does not want to borrow maths part 2 unless maths part 1 is borrowed? In how many ways can he choose the three books to be borrowed??
2t(5+6)-t4=108
??
c =48
d=40
p =-60
lcm =240 =>c =5 ,d =6 p =-4
now 11/40 part =11/40*240 =66
now let p is opened after x min frm c and d now given condition is that opening tym of p = to closing tym
=> 66 +11x +(11-4)x +6*11 =240
=>132 +18x =240 =>18x =108 =>x =6min
now this is the closing tym => until this time c and both works 2x (x before p +x with p) time =>totl time taken by c =totl tym taken by d =2x+6 =2*6+6 =18min
=> fraction filling of tank by c =18/48 =3/8
1/40th part diya hai Q me 11/40 kaise?
11/40 dia h bhai dekiyee aap 11/40 part of tank is filled dia h naaa…:)))
https://uploads.disquscdn.com/images/39c12586ec3e49a8b991ffd455ab0455b7c9062af7bc6bb75576f370ea7a44ce.png
bro…yha pey to 11/40 diya hua hhhh …:)))
after f5 aa gya …:))
…:)))
A boy has 3 library tickets and 8 books of his interest in the library of these 8, he does not want to borrow maths part 2 unless maths part 1 is borrowed? In how many ways can he choose the three books to be borrowed?.
total ways for selection of 3 books from 8 => 8c3 =56
now total toltl no ways for selecting book other than maths book both part =6c2 =15
so totl ways of selecting 3 books=56-15 =41
isme vo ek part 2 k place pr part1 prefer krta h …to apne dono part kyu nikale h 6c2 ????
nhi wo tbi maths k pehle part ko lega jb dusra b available ho to h jaise probablity nikalte h naa none ki like p(none) =1-p(all) same concept use kia yha pey mam…:)
Thanku soooo much sir…got it now :))))
ji mam shukriyaaa…aapka…:)
Two persons Raj and Ramu started working for a company in similar jobs on January 1, 1991. Raj’s initial monthly salary was Rs 400, which increases by Rs 40 after every year. Ramu’s initial monthly salary was Rs 500 which increases by Rs 20 after every six months. If these arrangements continue till December 31, 200. Find the total salary they received during that period.
ans 152400
raj’s salary increment
=> 400 +440+————————-+upto 10 terms
now sum to n terms of an ap is given by
s(n) =n/2(2a+(n-1)d)
=> r(s) =10/2(800+9*40) =5800
=> totl anuual salary incremnt =12*5800 =69600rs
now ramu’s salary increment
=>500+520+————————+upto 20 terms(1 year =2 half months so 10year = 20 half months)
=>ra(s)=20/2(1000+19*20) =13800
=> totl monthly salary inc.=6*13800 =82800
=> totl money recieved =69600+82800 =152400rs
bro apne 12 & 6 se multiply kyu kiya baad me
sum to nikal diya h na …increment kyu kiya h ???
1st 1 ko 12 se multiply isly kia becoz uski monthly salary h dusre ko 6 se multiply isly kia kyuki uski increment monthly h
🙂 ji shukriya sir apka…howz yr prep going on :))
6/10
thnxxx
thank u mam…nice questions…
can anyone explain ques 6 by LCM method..
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